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3(3x+5)=3(x-15)
We move all terms to the left:
3(3x+5)-(3(x-15))=0
We multiply parentheses
9x-(3(x-15))+15=0
We calculate terms in parentheses: -(3(x-15)), so:We get rid of parentheses
3(x-15)
We multiply parentheses
3x-45
Back to the equation:
-(3x-45)
9x-3x+45+15=0
We add all the numbers together, and all the variables
6x+60=0
We move all terms containing x to the left, all other terms to the right
6x=-60
x=-60/6
x=-10
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