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3(3x+5)=2(2x-3)+2x
We move all terms to the left:
3(3x+5)-(2(2x-3)+2x)=0
We multiply parentheses
9x-(2(2x-3)+2x)+15=0
We calculate terms in parentheses: -(2(2x-3)+2x), so:We get rid of parentheses
2(2x-3)+2x
We add all the numbers together, and all the variables
2x+2(2x-3)
We multiply parentheses
2x+4x-6
We add all the numbers together, and all the variables
6x-6
Back to the equation:
-(6x-6)
9x-6x+6+15=0
We add all the numbers together, and all the variables
3x+21=0
We move all terms containing x to the left, all other terms to the right
3x=-21
x=-21/3
x=-7
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