3(3x+5)(4x+5)=44

Solution for 3(3x+5)(4x+5)=44 equation:

3(3x+5)(4x+5)=44

We move all terms to the left:

3(3x+5)(4x+5)-(44)=0

We multiply parentheses ..

3(+12x^2+15x+20x+25)-44=0

We multiply parentheses

36x^2+45x+60x+75-44=0

We add all the numbers together, and all the variables

36x^2+105x+31=0

a = 36; b = 105; c = +31;
Δ = b2-4ac
Δ = 1052-4·36·31
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6561}=81$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-81}{2*36}=\frac{-186}{72}
=-2+7/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+81}{2*36}=\frac{-24}{72}
=-1/3
$