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3(3x+4)=2(x+1)+3
We move all terms to the left:
3(3x+4)-(2(x+1)+3)=0
We multiply parentheses
9x-(2(x+1)+3)+12=0
We calculate terms in parentheses: -(2(x+1)+3), so:We get rid of parentheses
2(x+1)+3
We multiply parentheses
2x+2+3
We add all the numbers together, and all the variables
2x+5
Back to the equation:
-(2x+5)
9x-2x-5+12=0
We add all the numbers together, and all the variables
7x+7=0
We move all terms containing x to the left, all other terms to the right
7x=-7
x=-7/7
x=-1
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