3(3x+3)=-6(1-x)+8x

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Solution for 3(3x+3)=-6(1-x)+8x equation: 



3(3x+3)=-6(1-x)+8x

We move all terms to the left:

3(3x+3)-(-6(1-x)+8x)=0

We add all the numbers together, and all the variables

3(3x+3)-(-6(-1x+1)+8x)=0

We multiply parentheses

9x-(-6(-1x+1)+8x)+9=0



We calculate terms in parentheses: -(-6(-1x+1)+8x), so:

-6(-1x+1)+8x

We add all the numbers together, and all the variables

8x-6(-1x+1)

We multiply parentheses

8x+6x-6

We add all the numbers together, and all the variables

14x-6

Back to the equation:

-(14x-6)



We get rid of parentheses

9x-14x+6+9=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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