3(3x+3)=-5(2x-4)+3x

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Solution for 3(3x+3)=-5(2x-4)+3x equation: 



3(3x+3)=-5(2x-4)+3x

We move all terms to the left:

3(3x+3)-(-5(2x-4)+3x)=0

We multiply parentheses

9x-(-5(2x-4)+3x)+9=0



We calculate terms in parentheses: -(-5(2x-4)+3x), so:

-5(2x-4)+3x

We add all the numbers together, and all the variables

3x-5(2x-4)

We multiply parentheses

3x-10x+20

We add all the numbers together, and all the variables

-7x+20

Back to the equation:

-(-7x+20)



We get rid of parentheses

9x+7x-20+9=0

We add all the numbers together, and all the variables

16x-11=0

We move all terms containing x to the left, all other terms to the right

16x=11

x=11/16

x=11/16

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