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3(3x+3)(5x+6)=0
We multiply parentheses ..
3(+15x^2+18x+15x+18)=0
We multiply parentheses
45x^2+54x+45x+54=0
We add all the numbers together, and all the variables
45x^2+99x+54=0
a = 45; b = 99; c = +54;
Δ = b2-4ac
Δ = 992-4·45·54
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-9}{2*45}=\frac{-108}{90} =-1+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+9}{2*45}=\frac{-90}{90} =-1 $
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