3(3x+2)-4(x-3)=38

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Solution for 3(3x+2)-4(x-3)=38 equation: 



3(3x+2)-4(x-3)=38

We move all terms to the left:

3(3x+2)-4(x-3)-(38)=0

We multiply parentheses

9x-4x+6+12-38=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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