3(3x+12)-20=16x+16-7x

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Solution for 3(3x+12)-20=16x+16-7x equation:


Simplifying
3(3x + 12) + -20 = 16x + 16 + -7x

Reorder the terms:
3(12 + 3x) + -20 = 16x + 16 + -7x
(12 * 3 + 3x * 3) + -20 = 16x + 16 + -7x
(36 + 9x) + -20 = 16x + 16 + -7x

Reorder the terms:
36 + -20 + 9x = 16x + 16 + -7x

Combine like terms: 36 + -20 = 16
16 + 9x = 16x + 16 + -7x

Reorder the terms:
16 + 9x = 16 + 16x + -7x

Combine like terms: 16x + -7x = 9x
16 + 9x = 16 + 9x

Add '-16' to each side of the equation.
16 + -16 + 9x = 16 + -16 + 9x

Combine like terms: 16 + -16 = 0
0 + 9x = 16 + -16 + 9x
9x = 16 + -16 + 9x

Combine like terms: 16 + -16 = 0
9x = 0 + 9x
9x = 9x

Add '-9x' to each side of the equation.
9x + -9x = 9x + -9x

Combine like terms: 9x + -9x = 0
0 = 9x + -9x

Combine like terms: 9x + -9x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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