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3(3x+1)=-2(2x-5)+3x
We move all terms to the left:
3(3x+1)-(-2(2x-5)+3x)=0
We multiply parentheses
9x-(-2(2x-5)+3x)+3=0
We calculate terms in parentheses: -(-2(2x-5)+3x), so:We get rid of parentheses
-2(2x-5)+3x
We add all the numbers together, and all the variables
3x-2(2x-5)
We multiply parentheses
3x-4x+10
We add all the numbers together, and all the variables
-1x+10
Back to the equation:
-(-1x+10)
9x+1x-10+3=0
We add all the numbers together, and all the variables
10x-7=0
We move all terms containing x to the left, all other terms to the right
10x=7
x=7/10
x=7/10
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