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3(3x+1)=-2(2x-3)
We move all terms to the left:
3(3x+1)-(-2(2x-3))=0
We multiply parentheses
9x-(-2(2x-3))+3=0
We calculate terms in parentheses: -(-2(2x-3)), so:We get rid of parentheses
-2(2x-3)
We multiply parentheses
-4x+6
Back to the equation:
-(-4x+6)
9x+4x-6+3=0
We add all the numbers together, and all the variables
13x-3=0
We move all terms containing x to the left, all other terms to the right
13x=3
x=3/13
x=3/13
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