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3(3x+1)+22(4-x)=6x-4(3x-2)
We move all terms to the left:
3(3x+1)+22(4-x)-(6x-4(3x-2))=0
We add all the numbers together, and all the variables
3(3x+1)+22(-1x+4)-(6x-4(3x-2))=0
We multiply parentheses
9x-22x-(6x-4(3x-2))+3+88=0
We calculate terms in parentheses: -(6x-4(3x-2)), so:We add all the numbers together, and all the variables
6x-4(3x-2)
We multiply parentheses
6x-12x+8
We add all the numbers together, and all the variables
-6x+8
Back to the equation:
-(-6x+8)
-13x-(-6x+8)+91=0
We get rid of parentheses
-13x+6x-8+91=0
We add all the numbers together, and all the variables
-7x+83=0
We move all terms containing x to the left, all other terms to the right
-7x=-83
x=-83/-7
x=11+6/7
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