3(3x+1)+2(4-x)=6x-4(3x-2)

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Solution for 3(3x+1)+2(4-x)=6x-4(3x-2) equation: 



3(3x+1)+2(4-x)=6x-4(3x-2)

We move all terms to the left:

3(3x+1)+2(4-x)-(6x-4(3x-2))=0

We add all the numbers together, and all the variables

3(3x+1)+2(-1x+4)-(6x-4(3x-2))=0

We multiply parentheses

9x-2x-(6x-4(3x-2))+3+8=0



We calculate terms in parentheses: -(6x-4(3x-2)), so:

6x-4(3x-2)

We multiply parentheses

6x-12x+8

We add all the numbers together, and all the variables

-6x+8

Back to the equation:

-(-6x+8)



We add all the numbers together, and all the variables

7x-(-6x+8)+11=0

We get rid of parentheses

7x+6x-8+11=0

We add all the numbers together, and all the variables

13x+3=0

We move all terms containing x to the left, all other terms to the right

13x=-3

x=-3/13

x=-3/13

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