3(3p-4)+2=3(p+2)+2

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Solution for 3(3p-4)+2=3(p+2)+2 equation: 



3(3p-4)+2=3(p+2)+2

We move all terms to the left:

3(3p-4)+2-(3(p+2)+2)=0

We multiply parentheses

9p-(3(p+2)+2)-12+2=0



We calculate terms in parentheses: -(3(p+2)+2), so:

3(p+2)+2

We multiply parentheses

3p+6+2

We add all the numbers together, and all the variables

3p+8

Back to the equation:

-(3p+8)



We add all the numbers together, and all the variables

9p-(3p+8)-10=0

We get rid of parentheses

9p-3p-8-10=0

We add all the numbers together, and all the variables

6p-18=0

We move all terms containing p to the left, all other terms to the right

6p=18

p=18/6

p=3

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