3(3m-2)-2(m-3)=-(m+5)-11

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Solution for 3(3m-2)-2(m-3)=-(m+5)-11 equation: 



3(3m-2)-2(m-3)=-(m+5)-11

We move all terms to the left:

3(3m-2)-2(m-3)-(-(m+5)-11)=0

We multiply parentheses

9m-2m-(-(m+5)-11)-6+6=0



We calculate terms in parentheses: -(-(m+5)-11), so:

-(m+5)-11

We get rid of parentheses

-m-5-11

We add all the numbers together, and all the variables

-1m-16

Back to the equation:

-(-1m-16)



We add all the numbers together, and all the variables

7m-(-1m-16)=0

We get rid of parentheses

7m+1m+16=0

We add all the numbers together, and all the variables

8m+16=0

We move all terms containing m to the left, all other terms to the right

8m=-16

m=-16/8

m=-2

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