3(3k-3)-7(k-6)=41

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Solution for 3(3k-3)-7(k-6)=41 equation:


Simplifying
3(3k + -3) + -7(k + -6) = 41

Reorder the terms:
3(-3 + 3k) + -7(k + -6) = 41
(-3 * 3 + 3k * 3) + -7(k + -6) = 41
(-9 + 9k) + -7(k + -6) = 41

Reorder the terms:
-9 + 9k + -7(-6 + k) = 41
-9 + 9k + (-6 * -7 + k * -7) = 41
-9 + 9k + (42 + -7k) = 41

Reorder the terms:
-9 + 42 + 9k + -7k = 41

Combine like terms: -9 + 42 = 33
33 + 9k + -7k = 41

Combine like terms: 9k + -7k = 2k
33 + 2k = 41

Solving
33 + 2k = 41

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-33' to each side of the equation.
33 + -33 + 2k = 41 + -33

Combine like terms: 33 + -33 = 0
0 + 2k = 41 + -33
2k = 41 + -33

Combine like terms: 41 + -33 = 8
2k = 8

Divide each side by '2'.
k = 4

Simplifying
k = 4

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