3(3k-10)+1=8(3/2k+2)

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Solution for 3(3k-10)+1=8(3/2k+2) equation: 



3(3k-10)+1=8(3/2k+2)

We move all terms to the left:

3(3k-10)+1-(8(3/2k+2))=0



Domain of the equation: 2k+2))!=0

k∈R



We multiply parentheses

9k-(8(3/2k+2))-30+1=0

We multiply all the terms by the denominator


9k*2k-30*2k+2))+1*2k+2))+2))-(8(3=0

Wy multiply elements

18k^2-60k+2))+1*2k+2))+2))-(8(3=0

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