3(3k-10)+1=8(3/2k+2

Solution for 3(3k-10)+1=8(3/2k+2 equation:

3(3k-10)+1=8(3/2k+2

We move all terms to the left:

3(3k-10)+1-(8(3/2k+2)=0


Domain of the equation: 2k+2)+1!=0

k∈R


We multiply parentheses

9k-(8(3/2k+2)+1-30=0

We multiply all the terms by the denominator


9k*2k+2)+1-30-(8(3=0

We add all the numbers together, and all the variables

9k*2k=0

Wy multiply elements

18k^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{36}=0$