3(3k+3)=5(4k-4)

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Solution for 3(3k+3)=5(4k-4) equation: 



3(3k+3)=5(4k-4)

We move all terms to the left:

3(3k+3)-(5(4k-4))=0

We multiply parentheses

9k-(5(4k-4))+9=0



We calculate terms in parentheses: -(5(4k-4)), so:

5(4k-4)

We multiply parentheses

20k-20

Back to the equation:

-(20k-20)



We get rid of parentheses

9k-20k+20+9=0

We add all the numbers together, and all the variables

-11k+29=0

We move all terms containing k to the left, all other terms to the right

-11k=-29

k=-29/-11

k=2+7/11

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