3(3c+s)=4(s+19)

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Solution for 3(3c+s)=4(s+19) equation:


Simplifying
3(3c + s) = 4(s + 19)
(3c * 3 + s * 3) = 4(s + 19)
(9c + 3s) = 4(s + 19)

Reorder the terms:
9c + 3s = 4(19 + s)
9c + 3s = (19 * 4 + s * 4)
9c + 3s = (76 + 4s)

Solving
9c + 3s = 76 + 4s

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3s' to each side of the equation.
9c + 3s + -3s = 76 + 4s + -3s

Combine like terms: 3s + -3s = 0
9c + 0 = 76 + 4s + -3s
9c = 76 + 4s + -3s

Combine like terms: 4s + -3s = 1s
9c = 76 + 1s

Divide each side by '9'.
c = 8.444444444 + 0.1111111111s

Simplifying
c = 8.444444444 + 0.1111111111s

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