3(3c+5)=2(10-c)

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Solution for 3(3c+5)=2(10-c) equation:



3(3c+5)=2(10-c)
We move all terms to the left:
3(3c+5)-(2(10-c))=0
We add all the numbers together, and all the variables
3(3c+5)-(2(-1c+10))=0
We multiply parentheses
9c-(2(-1c+10))+15=0
We calculate terms in parentheses: -(2(-1c+10)), so:
2(-1c+10)
We multiply parentheses
-2c+20
Back to the equation:
-(-2c+20)
We get rid of parentheses
9c+2c-20+15=0
We add all the numbers together, and all the variables
11c-5=0
We move all terms containing c to the left, all other terms to the right
11c=5
c=5/11
c=5/11

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