3(3b-4)-8(1+3b)=10

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Solution for 3(3b-4)-8(1+3b)=10 equation: 


Simplifying
3(3b + -4) + -8(1 + 3b) = 10

Reorder the terms:
3(-4 + 3b) + -8(1 + 3b) = 10
(-4 * 3 + 3b * 3) + -8(1 + 3b) = 10
(-12 + 9b) + -8(1 + 3b) = 10
-12 + 9b + (1 * -8 + 3b * -8) = 10
-12 + 9b + (-8 + -24b) = 10

Reorder the terms:
-12 + -8 + 9b + -24b = 10

Combine like terms: -12 + -8 = -20
-20 + 9b + -24b = 10

Combine like terms: 9b + -24b = -15b
-20 + -15b = 10

Solving
-20 + -15b = 10

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + -15b = 10 + 20

Combine like terms: -20 + 20 = 0
0 + -15b = 10 + 20
-15b = 10 + 20

Combine like terms: 10 + 20 = 30
-15b = 30

Divide each side by '-15'.
b = -2

Simplifying
b = -2

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