3(3b-1)+5(4b+3)=7

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Solution for 3(3b-1)+5(4b+3)=7 equation: 



3(3b-1)+5(4b+3)=7

We move all terms to the left:

3(3b-1)+5(4b+3)-(7)=0

We multiply parentheses

9b+20b-3+15-7=0

We add all the numbers together, and all the variables

29b+5=0

We move all terms containing b to the left, all other terms to the right

29b=-5

b=-5/29

b=-5/29

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