3(3b+2)=-6+12b

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Solution for 3(3b+2)=-6+12b equation: 



3(3b+2)=-6+12b

We move all terms to the left:

3(3b+2)-(-6+12b)=0

We add all the numbers together, and all the variables

3(3b+2)-(12b-6)=0

We multiply parentheses

9b-(12b-6)+6=0

We get rid of parentheses

9b-12b+6+6=0

We add all the numbers together, and all the variables

-3b+12=0

We move all terms containing b to the left, all other terms to the right

-3b=-12

b=-12/-3

b=+4

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