3(3Y-3)-2(2Y-2)=10

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Solution for 3(3Y-3)-2(2Y-2)=10 equation: 


Simplifying
3(3Y + -3) + -2(2Y + -2) = 10

Reorder the terms:
3(-3 + 3Y) + -2(2Y + -2) = 10
(-3 * 3 + 3Y * 3) + -2(2Y + -2) = 10
(-9 + 9Y) + -2(2Y + -2) = 10

Reorder the terms:
-9 + 9Y + -2(-2 + 2Y) = 10
-9 + 9Y + (-2 * -2 + 2Y * -2) = 10
-9 + 9Y + (4 + -4Y) = 10

Reorder the terms:
-9 + 4 + 9Y + -4Y = 10

Combine like terms: -9 + 4 = -5
-5 + 9Y + -4Y = 10

Combine like terms: 9Y + -4Y = 5Y
-5 + 5Y = 10

Solving
-5 + 5Y = 10

Solving for variable 'Y'.

Move all terms containing Y to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 5Y = 10 + 5

Combine like terms: -5 + 5 = 0
0 + 5Y = 10 + 5
5Y = 10 + 5

Combine like terms: 10 + 5 = 15
5Y = 15

Divide each side by '5'.
Y = 3

Simplifying
Y = 3

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