3(36x+20)=12(4x+40)

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Solution for 3(36x+20)=12(4x+40) equation: 



3(36x+20)=12(4x+40)

We move all terms to the left:

3(36x+20)-(12(4x+40))=0

We multiply parentheses

108x-(12(4x+40))+60=0



We calculate terms in parentheses: -(12(4x+40)), so:

12(4x+40)

We multiply parentheses

48x+480

Back to the equation:

-(48x+480)



We get rid of parentheses

108x-48x-480+60=0

We add all the numbers together, and all the variables

60x-420=0

We move all terms containing x to the left, all other terms to the right

60x=420

x=420/60

x=7

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