3(30+z)=4(z+19)

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Solution for 3(30+z)=4(z+19) equation: 



3(30+z)=4(z+19)

We move all terms to the left:

3(30+z)-(4(z+19))=0

We add all the numbers together, and all the variables

3(z+30)-(4(z+19))=0

We multiply parentheses

3z-(4(z+19))+90=0



We calculate terms in parentheses: -(4(z+19)), so:

4(z+19)

We multiply parentheses

4z+76

Back to the equation:

-(4z+76)



We get rid of parentheses

3z-4z-76+90=0

We add all the numbers together, and all the variables

-1z+14=0

We move all terms containing z to the left, all other terms to the right

-z=-14

z=-14/-1

z=+14

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