3(30+n)=4(n+19)

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Solution for 3(30+n)=4(n+19) equation: 



3(30+n)=4(n+19)

We move all terms to the left:

3(30+n)-(4(n+19))=0

We add all the numbers together, and all the variables

3(n+30)-(4(n+19))=0

We multiply parentheses

3n-(4(n+19))+90=0



We calculate terms in parentheses: -(4(n+19)), so:

4(n+19)

We multiply parentheses

4n+76

Back to the equation:

-(4n+76)



We get rid of parentheses

3n-4n-76+90=0

We add all the numbers together, and all the variables

-1n+14=0

We move all terms containing n to the left, all other terms to the right

-n=-14

n=-14/-1

n=+14

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