3(3/4)y=3

Solution for 3(3/4)y=3 equation:

3(3/4)y=3

We move all terms to the left:

3(3/4)y-(3)=0


Domain of the equation: 4)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

3(+3/4)y-3=0

We multiply parentheses

9y^2-3=0

a = 9; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·9·(-3)
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{3}}{2*9}=\frac{0-6\sqrt{3}}{18}
=-\frac{6\sqrt{3}}{18}
=-\frac{\sqrt{3}}{3}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{3}}{2*9}=\frac{0+6\sqrt{3}}{18}
=\frac{6\sqrt{3}}{18}
=\frac{\sqrt{3}}{3}
$