3(3-x)+5=6-2(3x-1)

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Solution for 3(3-x)+5=6-2(3x-1) equation: 



3(3-x)+5=6-2(3x-1)

We move all terms to the left:

3(3-x)+5-(6-2(3x-1))=0

We add all the numbers together, and all the variables

3(-1x+3)-(6-2(3x-1))+5=0

We multiply parentheses

-3x-(6-2(3x-1))+9+5=0



We calculate terms in parentheses: -(6-2(3x-1)), so:

6-2(3x-1)

determiningTheFunctionDomain
-2(3x-1)+6

We multiply parentheses

-6x+2+6

We add all the numbers together, and all the variables

-6x+8

Back to the equation:

-(-6x+8)



We add all the numbers together, and all the variables

-3x-(-6x+8)+14=0

We get rid of parentheses

-3x+6x-8+14=0

We add all the numbers together, and all the variables

3x+6=0

We move all terms containing x to the left, all other terms to the right

3x=-6

x=-6/3

x=-2

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