3(3-r)+2(1-r)=6

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Solution for 3(3-r)+2(1-r)=6 equation: 



3(3-r)+2(1-r)=6

We move all terms to the left:

3(3-r)+2(1-r)-(6)=0

We add all the numbers together, and all the variables

3(-1r+3)+2(-1r+1)-6=0

We multiply parentheses

-3r-2r+9+2-6=0

We add all the numbers together, and all the variables

-5r+5=0

We move all terms containing r to the left, all other terms to the right

-5r=-5

r=-5/-5

r=1

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