3(3-i)+1=31

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Solution for 3(3-i)+1=31 equation: 



3(3-i)+1=31

We move all terms to the left:

3(3-i)+1-(31)=0

We add all the numbers together, and all the variables

3(-1i+3)+1-31=0

We add all the numbers together, and all the variables

3(-1i+3)-30=0

We multiply parentheses

-3i+9-30=0

We add all the numbers together, and all the variables

-3i-21=0

We move all terms containing i to the left, all other terms to the right

-3i=21

i=21/-3

i=-7

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