3(3-2x)=2(4x+5)

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Solution for 3(3-2x)=2(4x+5) equation: 



3(3-2x)=2(4x+5)

We move all terms to the left:

3(3-2x)-(2(4x+5))=0

We add all the numbers together, and all the variables

3(-2x+3)-(2(4x+5))=0

We multiply parentheses

-6x-(2(4x+5))+9=0



We calculate terms in parentheses: -(2(4x+5)), so:

2(4x+5)

We multiply parentheses

8x+10

Back to the equation:

-(8x+10)



We get rid of parentheses

-6x-8x-10+9=0

We add all the numbers together, and all the variables

-14x-1=0

We move all terms containing x to the left, all other terms to the right

-14x=1

x=1/-14

x=-1/14

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