3(3+s)=4(4s-2)+4

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Solution for 3(3+s)=4(4s-2)+4 equation: 



3(3+s)=4(4s-2)+4

We move all terms to the left:

3(3+s)-(4(4s-2)+4)=0

We add all the numbers together, and all the variables

3(s+3)-(4(4s-2)+4)=0

We multiply parentheses

3s-(4(4s-2)+4)+9=0



We calculate terms in parentheses: -(4(4s-2)+4), so:

4(4s-2)+4

We multiply parentheses

16s-8+4

We add all the numbers together, and all the variables

16s-4

Back to the equation:

-(16s-4)



We get rid of parentheses

3s-16s+4+9=0

We add all the numbers together, and all the variables

-13s+13=0

We move all terms containing s to the left, all other terms to the right

-13s=-13

s=-13/-13

s=1

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