3(3+4m)-6=48

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Solution for 3(3+4m)-6=48 equation: 



3(3+4m)-6=48

We move all terms to the left:

3(3+4m)-6-(48)=0

We add all the numbers together, and all the variables

3(4m+3)-6-48=0

We add all the numbers together, and all the variables

3(4m+3)-54=0

We multiply parentheses

12m+9-54=0

We add all the numbers together, and all the variables

12m-45=0

We move all terms containing m to the left, all other terms to the right

12m=45

m=45/12

m=3+3/4

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