3(3+2k)=(-3)(1k-6)

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Solution for 3(3+2k)=(-3)(1k-6) equation: 



3(3+2k)=(-3)(1k-6)

We move all terms to the left:

3(3+2k)-((-3)(1k-6))=0

We add all the numbers together, and all the variables

3(2k+3)-((-3)(k-6))=0

We multiply parentheses

6k-((-3)(k-6))+9=0

We multiply parentheses ..

6k-((-3k+18))+9=0



We calculate terms in parentheses: -((-3k+18)), so:

(-3k+18)

We get rid of parentheses

-3k+18

Back to the equation:

-(-3k+18)



We get rid of parentheses

6k+3k-18+9=0

We add all the numbers together, and all the variables

9k-9=0

We move all terms containing k to the left, all other terms to the right

9k=9

k=9/9

k=1

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