3(3+10y)+7y=31

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Solution for 3(3+10y)+7y=31 equation: 



3(3+10y)+7y=31

We move all terms to the left:

3(3+10y)+7y-(31)=0

We add all the numbers together, and all the variables

3(10y+3)+7y-31=0

We add all the numbers together, and all the variables

7y+3(10y+3)-31=0

We multiply parentheses

7y+30y+9-31=0

We add all the numbers together, and all the variables

37y-22=0

We move all terms containing y to the left, all other terms to the right

37y=22

y=22/37

y=22/37

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