3(2z-6)+3=2(z+6)+1

Solution for 3(2z-6)+3=2(z+6)+1 equation:

3(2z-6)+3=2(z+6)+1

We move all terms to the left:

3(2z-6)+3-(2(z+6)+1)=0

We multiply parentheses

6z-(2(z+6)+1)-18+3=0


We calculate terms in parentheses: -(2(z+6)+1), so:

2(z+6)+1

We multiply parentheses

2z+12+1

We add all the numbers together, and all the variables

2z+13

Back to the equation:

-(2z+13)


We add all the numbers together, and all the variables

6z-(2z+13)-15=0

We get rid of parentheses

6z-2z-13-15=0

We add all the numbers together, and all the variables

4z-28=0

We move all terms containing z to the left, all other terms to the right

4z=28

z=28/4

z=7