3(2z-4)=3(z-4)

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Solution for 3(2z-4)=3(z-4) equation:


Simplifying
3(2z + -4) = 3(z + -4)

Reorder the terms:
3(-4 + 2z) = 3(z + -4)
(-4 * 3 + 2z * 3) = 3(z + -4)
(-12 + 6z) = 3(z + -4)

Reorder the terms:
-12 + 6z = 3(-4 + z)
-12 + 6z = (-4 * 3 + z * 3)
-12 + 6z = (-12 + 3z)

Add '12' to each side of the equation.
-12 + 12 + 6z = -12 + 12 + 3z

Combine like terms: -12 + 12 = 0
0 + 6z = -12 + 12 + 3z
6z = -12 + 12 + 3z

Combine like terms: -12 + 12 = 0
6z = 0 + 3z
6z = 3z

Solving
6z = 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
6z + -3z = 3z + -3z

Combine like terms: 6z + -3z = 3z
3z = 3z + -3z

Combine like terms: 3z + -3z = 0
3z = 0

Divide each side by '3'.
z = 0

Simplifying
z = 0

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