3(2z-2)=5(z-5)

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Solution for 3(2z-2)=5(z-5) equation:


Simplifying
3(2z + -2) = 5(z + -5)

Reorder the terms:
3(-2 + 2z) = 5(z + -5)
(-2 * 3 + 2z * 3) = 5(z + -5)
(-6 + 6z) = 5(z + -5)

Reorder the terms:
-6 + 6z = 5(-5 + z)
-6 + 6z = (-5 * 5 + z * 5)
-6 + 6z = (-25 + 5z)

Solving
-6 + 6z = -25 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-6 + 6z + -5z = -25 + 5z + -5z

Combine like terms: 6z + -5z = 1z
-6 + 1z = -25 + 5z + -5z

Combine like terms: 5z + -5z = 0
-6 + 1z = -25 + 0
-6 + 1z = -25

Add '6' to each side of the equation.
-6 + 6 + 1z = -25 + 6

Combine like terms: -6 + 6 = 0
0 + 1z = -25 + 6
1z = -25 + 6

Combine like terms: -25 + 6 = -19
1z = -19

Divide each side by '1'.
z = -19

Simplifying
z = -19

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