3(2z-2)=5(z+)

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Solution for 3(2z-2)=5(z+) equation: 



3(2z-2)=5(z+)

We move all terms to the left:

3(2z-2)-(5(z+))=0

We add all the numbers together, and all the variables

3(2z-2)-(5(+z))=0

We multiply parentheses

6z-(5(+z))-6=0



We calculate terms in parentheses: -(5(+z)), so:

5(+z)

We multiply parentheses

5z

Back to the equation:

-(5z)



We add all the numbers together, and all the variables

z-6=0

We move all terms containing z to the left, all other terms to the right

z=6

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