3(2z-10)=30

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Solution for 3(2z-10)=30 equation: 



3(2z-10)=30

We move all terms to the left:

3(2z-10)-(30)=0

We multiply parentheses

6z-30-30=0

We add all the numbers together, and all the variables

6z-60=0

We move all terms containing z to the left, all other terms to the right

6z=60

z=60/6

z=10

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