3(2z-1)4(z+3)=5(2z-1)+4(3z-1)

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Solution for 3(2z-1)4(z+3)=5(2z-1)+4(3z-1) equation: 



3(2z-1)4(z+3)=5(2z-1)+4(3z-1)

We move all terms to the left:

3(2z-1)4(z+3)-(5(2z-1)+4(3z-1))=0



We calculate terms in parentheses: -(5(2z-1)+4(3z-1)), so:

5(2z-1)+4(3z-1)

We multiply parentheses

10z+12z-5-4

We add all the numbers together, and all the variables

22z-9

Back to the equation:

-(22z-9)



We get rid of parentheses

3(2z-1)4(z+3)-22z+9=0

We add all the numbers together, and all the variables

-22z+3(2z-1)4(z+3)+9=0

We move all terms containing z to the left, all other terms to the right

-22z+3(2z-1)4(z+3)=-9

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