3(2z-1)-7=6z-10

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Solution for 3(2z-1)-7=6z-10 equation:


Simplifying
3(2z + -1) + -7 = 6z + -10

Reorder the terms:
3(-1 + 2z) + -7 = 6z + -10
(-1 * 3 + 2z * 3) + -7 = 6z + -10
(-3 + 6z) + -7 = 6z + -10

Reorder the terms:
-3 + -7 + 6z = 6z + -10

Combine like terms: -3 + -7 = -10
-10 + 6z = 6z + -10

Reorder the terms:
-10 + 6z = -10 + 6z

Add '10' to each side of the equation.
-10 + 10 + 6z = -10 + 10 + 6z

Combine like terms: -10 + 10 = 0
0 + 6z = -10 + 10 + 6z
6z = -10 + 10 + 6z

Combine like terms: -10 + 10 = 0
6z = 0 + 6z
6z = 6z

Add '-6z' to each side of the equation.
6z + -6z = 6z + -6z

Combine like terms: 6z + -6z = 0
0 = 6z + -6z

Combine like terms: 6z + -6z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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