3(2z-0)=-12

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Solution for 3(2z-0)=-12 equation: 



3(2z-0)=-12

We move all terms to the left:

3(2z-0)-(-12)=0

We add all the numbers together, and all the variables

3(+2z)-(-12)=0

We add all the numbers together, and all the variables

3(+2z)+12=0

We multiply parentheses

6z+12=0

We move all terms containing z to the left, all other terms to the right

6z=-12

z=-12/6

z=-2

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