3(2z+5)=7z

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Solution for 3(2z+5)=7z equation: 



3(2z+5)=7z

We move all terms to the left:

3(2z+5)-(7z)=0

We add all the numbers together, and all the variables

-7z+3(2z+5)=0

We multiply parentheses

-7z+6z+15=0

We add all the numbers together, and all the variables

-1z+15=0

We move all terms containing z to the left, all other terms to the right

-z=-15

z=-15/-1

z=+15

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