3(2z+5)+2(4z-3)=79

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Solution for 3(2z+5)+2(4z-3)=79 equation:


Simplifying
3(2z + 5) + 2(4z + -3) = 79

Reorder the terms:
3(5 + 2z) + 2(4z + -3) = 79
(5 * 3 + 2z * 3) + 2(4z + -3) = 79
(15 + 6z) + 2(4z + -3) = 79

Reorder the terms:
15 + 6z + 2(-3 + 4z) = 79
15 + 6z + (-3 * 2 + 4z * 2) = 79
15 + 6z + (-6 + 8z) = 79

Reorder the terms:
15 + -6 + 6z + 8z = 79

Combine like terms: 15 + -6 = 9
9 + 6z + 8z = 79

Combine like terms: 6z + 8z = 14z
9 + 14z = 79

Solving
9 + 14z = 79

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 14z = 79 + -9

Combine like terms: 9 + -9 = 0
0 + 14z = 79 + -9
14z = 79 + -9

Combine like terms: 79 + -9 = 70
14z = 70

Divide each side by '14'.
z = 5

Simplifying
z = 5

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