3(2z+25)=2(z-1)

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Solution for 3(2z+25)=2(z-1) equation: 



3(2z+25)=2(z-1)

We move all terms to the left:

3(2z+25)-(2(z-1))=0

We multiply parentheses

6z-(2(z-1))+75=0



We calculate terms in parentheses: -(2(z-1)), so:

2(z-1)

We multiply parentheses

2z-2

Back to the equation:

-(2z-2)



We get rid of parentheses

6z-2z+2+75=0

We add all the numbers together, and all the variables

4z+77=0

We move all terms containing z to the left, all other terms to the right

4z=-77

z=-77/4

z=-19+1/4

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