3(2z+25)-2(z-1)=7/8

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Solution for 3(2z+25)-2(z-1)=7/8 equation: 



3(2z+25)-2(z-1)=7/8

We move all terms to the left:

3(2z+25)-2(z-1)-(7/8)=0

We add all the numbers together, and all the variables

3(2z+25)-2(z-1)-(+7/8)=0

We multiply parentheses

6z-2z+75+2-(+7/8)=0

We get rid of parentheses

6z-2z+75+2-7/8=0

We multiply all the terms by the denominator


6z*8-2z*8-7+75*8+2*8=0

We add all the numbers together, and all the variables

6z*8-2z*8+609=0

Wy multiply elements

48z-16z+609=0

We add all the numbers together, and all the variables

32z+609=0

We move all terms containing z to the left, all other terms to the right

32z=-609

z=-609/32

z=-19+1/32

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