3(2z+2)=5(z-1)+14

Solution for 3(2z+2)=5(z-1)+14 equation:

Simplifying
3(2z + 2) = 5(z + -1) + 14

Reorder the terms:
3(2 + 2z) = 5(z + -1) + 14
(2 * 3 + 2z * 3) = 5(z + -1) + 14
(6 + 6z) = 5(z + -1) + 14

Reorder the terms:
6 + 6z = 5(-1 + z) + 14
6 + 6z = (-1 * 5 + z * 5) + 14
6 + 6z = (-5 + 5z) + 14

Reorder the terms:
6 + 6z = -5 + 14 + 5z

Combine like terms: -5 + 14 = 9
6 + 6z = 9 + 5z

Solving
6 + 6z = 9 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
6 + 6z + -5z = 9 + 5z + -5z

Combine like terms: 6z + -5z = 1z
6 + 1z = 9 + 5z + -5z

Combine like terms: 5z + -5z = 0
6 + 1z = 9 + 0
6 + 1z = 9

Add '-6' to each side of the equation.
6 + -6 + 1z = 9 + -6

Combine like terms: 6 + -6 = 0
0 + 1z = 9 + -6
1z = 9 + -6

Combine like terms: 9 + -6 = 3
1z = 3

Divide each side by '1'.
z = 3

Simplifying
z = 3